All categories

3 years ago

PLEASE HELP ITS DUE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

tia_tia [17]3 years ago

3 0

Answer:

Angle 3 = 103

Angle 4 = 77

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180 so to find angle 3:

180 - (52+25) = 103

Angle 3 and angle 4 are supplementary so the measure of angle 4:

180 - 103 = 77

Angle 1 and angle 2 and angle 3 are the interior angles of the triangle and their sum is 180 so is the sum of angle 3 and angle 4

The sum of two interior angles in a triangle is equal to an exterior angle that is supplementary to the third interior angle so the sum of angle 1 and angle 2 is equal to angle 4

You might be interested in

If a =5 and b=3 what is the value of the 2a-3b+3a

34kurt

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

(2×5) - (3×3) + (3×5)

10 - 9 + 15 = 16

6 0

3 years ago

Is the relationship between the 6s in 664 and 668 different in any way? Explain why or why not

Shkiper50 [21]

No. Because in both the 6 to the left is 10 times the value of the 6 on the right.

5 0

3 years ago

A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major

SOVA2 [1]

the Solution

$Pr(\text{STEM)}=\frac{158}{401}=0.394$ $Pr(\text{Sophomore)}=\frac{87}{401}=0.217$ $Pr(sophomore|Non-stem)=\frac{68}{401}=0.170$ $Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315$

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

$\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}$ $\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}$ $Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})$ $=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147$

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0

1 year ago

Given the following functions f(x) and g(x), solve f over g(−4) and select the correct answer below:

marishachu [46]

$\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\f(x)=4x-4;\ g(x)=x-1\\\\f(-4)=4\cdot(-4)-4=-16-4=-20\\\\g(-4)=-4-1=-5\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{-20}{-4}=4$

5 0

4 years ago

Read 2 more answers

Cos(2x) + sin^2(x) = 0

zloy xaker [14]

cos(2θ) + sin²(θ) = 0

Half-angle identity:

cos(2θ) + (1 - cos(2θ))/2 = 0

Simplify:

2 cos(2θ) + 1 - cos(2θ) = 0

cos(2θ) = -1

Solve for θ :

2θ = arccos(-1) + 2nπ

2θ = π + 2nπ

θ = π/2 + nπ

where n is any integer.

7 0

3 years ago