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nasty-shy [4]
2 years ago
10

URGENT!!! 30 POINTS!!!Expand log(1/2)(3x^2/2) using properties and rules for logarithms.

Mathematics
1 answer:
Korvikt [17]2 years ago
6 0

\log_\frac{1}{2}\left(\dfrac{3x^2}{2}\right)=\log_\frac{1}{2}3x^2-\log_\frac{1}{2}2=\log_\frac{1}{2}3+\log_\frac{1}{2}x^2-\log_\frac{1}{2}2\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)-\log_\frac{1}{2}\left(\dfrac{1}{2}\right)^{-1}\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)-\left[-\log_\frac{1}{2}\left(\dfrac{1}{2}\right)\right]\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)+\log_\frac{1}{2}\left(\dfrac{1}{2}\right)\\\\=\boxed{\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)+1}

Used:\\\\\log_a\dfrac{b}{c}=\log_ab-\log_ac\\\\\log_a(bc)=\log_ab+\log_ac\\\\\log_ab^n=n\log_ab\\\\\log_aa=1

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For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9
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Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

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Answer:

D to C

Step-by-step explanation:

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6 0
2 years ago
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