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nasty-shy [4]
3 years ago
10

URGENT!!! 30 POINTS!!!Expand log(1/2)(3x^2/2) using properties and rules for logarithms.

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

\log_\frac{1}{2}\left(\dfrac{3x^2}{2}\right)=\log_\frac{1}{2}3x^2-\log_\frac{1}{2}2=\log_\frac{1}{2}3+\log_\frac{1}{2}x^2-\log_\frac{1}{2}2\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)-\log_\frac{1}{2}\left(\dfrac{1}{2}\right)^{-1}\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)-\left[-\log_\frac{1}{2}\left(\dfrac{1}{2}\right)\right]\\\\=\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)+\log_\frac{1}{2}\left(\dfrac{1}{2}\right)\\\\=\boxed{\log_\frac{1}{2}(3)+2\log_\frac{1}{2}(x)+1}

Used:\\\\\log_a\dfrac{b}{c}=\log_ab-\log_ac\\\\\log_a(bc)=\log_ab+\log_ac\\\\\log_ab^n=n\log_ab\\\\\log_aa=1

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Answer:

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Step-by-step explanation:

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3 years ago
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Suppose F⃗ (x,y)=(x+3)i⃗ +(6y+3)j⃗ . Use the fundamental theorem of line integrals to calculate the following.
Scorpion4ik [409]

In order to use the fundamental theorem of line integrals, you need to find a scalar potential function - that is, a scalar function <em>f(x, y)</em> for which

grad <em>f(x, y)</em> = <em>F</em><em>(x, y)</em>

This amounts to solving for <em>f</em> such that

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Integrating both sides of the first equation with respect to <em>x</em> gives

<em>f</em> = 1/2 <em>x</em> ^2 + 3<em>x</em> + <em>g(y)</em>

Differentiating with respect to <em>y</em> gives

∂<em>f</em>/∂<em>y</em> = d<em>g</em>/d<em>y</em> = 6<em>y</em> + 3

Solving for <em>g</em> gives

<em>g</em> = ∫ (6<em>y</em> + 3) d<em>y</em> = 3<em>y</em> ^2 + 3<em>y</em> + <em>C</em>

and hence

<em>f(x, y)</em> = 1/2 <em>x</em> ^2 + 3<em>x</em> + 3<em>y</em> ^2 + 3<em>y</em> + <em>C</em>

<em />

(a) By the fundamental theorem, the integral of <em>F</em> along any path starting at the point <em>P</em> (1, 0) and ending at <em>Q</em> (3, 3) is

∫ <em>F</em><em>(x, y)</em> • d<em>r</em> = <em>f</em> (3, 3) - <em>f</em> (1, 0) = 99/2 - 7/2 = 46

(b) Now we're talking about a closed path, so the integral is simply 0. We can verify this by checking the integral over the origin-containing paths:

• From the origin to <em>P</em> :

∫ <em>F</em><em>(x, y)</em> • d<em>r</em> = <em>f</em> (1, 0) - <em>f</em> (0, 0) = 7/2 - 0 = 7/2

• From <em>Q</em> back to the origin:

∫ <em>F</em><em>(x, y)</em> • d<em>r</em> = <em>f</em> (0, 0) - <em>f</em> (3, 3) = 0 - 99/2 = -99/2

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Answer:

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Step-by-step explanation:

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Answer:

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