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Wewaii [24]
3 years ago
13

Calculate the value of x in each case​

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Exact answer: x = \frac{\sqrt{601}}{2}\\\\

Approximate answer: x \approx 12.2577

====================================================

How to find the answer:

Focus on the largest triangle. It appears to be a right triangle. If so, then we can use the pythagorean theorem to get the following:

a^2 + b^2 = c^2\\\\a^2 + 12^2 = 13^2\\\\a^2 + 144 = 169\\\\a^2 = 169 - 144\\\\a^2 = 25\\\\a = \sqrt{25}\\\\a = 5

The horizontal leg of the largest right triangle is 5 units long.

The identical single tickmarks tell us that the horizontal leg is cut into two smaller pieces of equal length.

Each smaller piece is 5/2 = 2.5 units long.

------------------------------

Now focus on the smaller skinny right triangle with legs a = 2.5, b = 12 and hypotenuse c = x.

Use the pythagorean theorem again to find the hypotenuse x.

2.5^2 + 12^2 = c^2\\\\6.25 + 144 = x^2\\\\150.25 = x^2\\\\x^2 = 150.25\\\\x = \sqrt{150.25}\\\\x = \sqrt{\frac{601}{4}}\\\\x = \frac{\sqrt{601}}{\sqrt{4}}\\\\x = \frac{\sqrt{601}}{2}\\\\x \approx 12.2577

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m - 2/3 + 1/4 = 2/12

m = 2/12 - 3/12 + 8/12

m = 7/12

7 0
3 years ago
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Niu has decorated x cards. He started with 24 stickers, and he used 4 stickers per card. Which expressions can we use to describ
Kisachek [45]

Answer:

24-4x

Step-by-step explanation:

We have been given that Niu has decorated x cards. He started with 24 stickers and he used 4 stickers per card. So stickers used in x cards will be 4x.

As initial number of stickers was 24, so we can find number of stickers left after decorating x cards by subtracting number of stickers used in x cards from 24.

\text{Number of stickers that Niu has left}=24-4x

Therefore, the expression 24-4x will represent the number of stickers that Niu has left after decorating x cards.


7 0
4 years ago
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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

Diagonal 2(BD) = \sqrt{(2-2)^2+(3+5)^2} = 8 units

Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

                                                       = \frac{1}{2}\times 4\times 8

                                                       = 16 units²

Therefore, area of the given rhombus is 16 units².

5 0
3 years ago
Find the​ mean, median, and mode of the​ data, if possible. If any of these measures cannot be found or a measure does not repre
Ber [7]

Answer:

The mean cholesterol levels

= 173873.7

Step-by-step explanation:

For The mean

The mean is going to be sum of the numbers divide by the number

Mean = (130130 +145145+ 215215 +170170+ 165165 +225225+ 240240 +185185+ 130130 +132132 )/10

Mean =1738737/10

= 173873.7

For Median

Wee arrange ascending order

130130, 130130, 132132, 145145, 165165, 170170, 185185, 215215, 225225, 240240

Median = (165165+170170)/2

Median = 335335/2

Median = 167667.5

Mode = 130130

4 0
3 years ago
Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16
sweet-ann [11.9K]

Answer:

x=\frac{1}{4}

Step-by-step explanation:

<u>Given:</u>

2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)

<u>Use the Power Rule Law:</u>

log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)

<u>Use the Quotient Rule Law:</u>

log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})

<u>Use the Product Rule Law:</u>

log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})

<u>Simplify:</u>

log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})

\frac{4}{9}=\frac{8\sqrt{x}}{9}

4=8\sqrt{x}

\frac{4}{8}=\sqrt{x}

\frac{1}{2}=\sqrt{x}

\frac{1}{4}=x

5 0
2 years ago
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