There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!
Start with the first sentence.
x + y + z = 6.0
Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.
0.7 + y + z = 6.0
Now I'll subtract 0.7 from both sides to see what y and z have to add up to.
0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3
Now I'll choose a random number for y that's less than 5.3.
2.6 + z = 5.3
And subtract 2.6 from both sides to find z.
2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7
And now we have our numbers!
x = <u>0.7</u>
y = <u>2.6</u>
z = <u>2.7</u>
Answer:
Khan Academy is a great website for Algebra l math
If you have the time and money Kumon is a good in-person learning assistance (I-H level is about algebra I)
Step-by-step explanation:
Answer:
-3
Step-by-step explanation:
9-3(2)2
9-(6)2
9-12
-3
X + y = 1.....multiply by -2
2x - 3y = -30
-----------------
-2x - 2y = -2 (result of multiplying by -2)
2x - 3y = -30
----------------add
-5y = -32
y = -32/-5
y = 32/5 or 6.4 <===
The last one because the other ones only go to the positive side and not the negative too since the cube root
