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Slav-nsk [51]
2 years ago
15

How to use words to describe the two ways you can think about 8 X 5 = 40 as a comparison?

Mathematics
2 answers:
stiks02 [169]2 years ago
7 0

Answer:

opo

Step-by-step explanation:

tulog kana po, goodnight

scoray [572]2 years ago
4 0
In order to use words to describe ways you can compare things or anything really it’s important to learn the alphabet to write out these ideas and learn the language you’re trying to describe it in, and then study the concept to be able to describe or compare it! Hope this helps :)
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A word problem for the expression 5+(-2) The sum will be three i just need a word problem
ioda

Answer:

Mikey had 5 cookies. His friend took 2 with him when he left. How many cookies does Mikey have left?

Step-by-step explanation:

Here, 5 would be the starting amount.

-2 would be the amount taken away.

3 would be our final answer.

6 0
3 years ago
Rewrite the product as a power:<br> <img src="https://tex.z-dn.net/?f=%28-a%29%5E%7B3%7D%20b%5E%7B3%7D" id="TexFormula1" title="
anastassius [24]

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{ - a}^{3} . {b}^{3}  = ( { - a \times b})^{3}  = ( { - ab})^{3}  \\

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4 0
3 years ago
Find the quotient. Write your answer in standard form. : 3-i/3+i
s344n2d4d5 [400]
The answer is <span>C. 4/5 - 3/5 i
</span>
\frac{3-i}{3+i} = \frac{(3-i)(3-i)}{(3+i)(3-i)} \\  \\ &#10;(a+b)(a-b) =  a^{2} -b^{2}  \\  \\ &#10;\frac{(3-i)(3-i)}{(3+i)(3-i)}= \frac{ (3-i)^{2} }{3^{2}-i^{2} } \\  \\ &#10;(a-b)^{2} =a^{2}-2ab+b^{2} \\  \\ &#10; \frac{ (3-i)^{2} }{3^{2}-i^{2} } = \frac{3^{2}-2*3*i+i^{2}  }{3^{2}-i^{2} } = \frac{9-6i+i^{2}}{9-i^{2}}  \\  \\ &#10;i =  \sqrt{-1}  \\ i^{2}=-1 \\  \\ &#10;\frac{9-6i+i^{2}}{9-i^{2}} = \frac{9-6i-1}{9+1} = \frac{8-6i}{10}= \frac{8}{10}- \frac{6i}{10}= \frac{4}{5}- \frac{3}{5}i
8 0
3 years ago
Find the value of x if p ll q​
Stolb23 [73]

Answer:

maybe you can attach the screenshot of the task?

4 0
2 years ago
Can you help me with these question?​
alekssr [168]
The line of best fit looks correct . has a positive correlation. the slope is 1 by using your y2-y1 over x2-x1 . the population in year 2,000 is 40
7 0
3 years ago
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