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2 years ago

I dont understand can someone help?

Mathematics

1 answer:

nalin [4]2 years ago

3 0

First you need to find area of square which is side x side which is 8x8 which is 64. Then you find the side of the triangle which is 14-8 which is 6 then you need to find the height of the dotted line I’m pretty sure there’s a formula but it looks like it’s 8 because it looks like a square so then the formula of a triangle is base times height divided by two so the base is 6 and height is 8 so 6x8 which is 48 and divided by two is 24 then you add the area of the triangle and the area of the square which is 64 so 64+24 which is 88 so I’m pretty sure the area is 88 then just put whatever units after :)

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Calculate the lateral area of the cube if the perimeter of the base is 12 units

Brums [2.3K]

The lateral area of the cube is 36 sq units

Explanation:

Given:

Perimeter of the base of the cube = 12 units

Base of the cube has 4 sides

So, the perimeter of the base = 4a

where,

a is the length of one side

Thus,

4a = 12 units

a = 3 units

Lateral surface area of the cube = 4a²

A = 4 X (3)²

A = 36 sq units

Therefore, the lateral area of the cube is 36 sq units

4 0

3 years ago

What is a formula for the nth term of the given sequence? 36, 24, 16...

SpyIntel [72]

Answer:

The formula to find the nth term of the given sequence is 54 · $\frac{2}{3} ^{n}$

Step-by-step explanation:

The formula for nth term of an geometric progression is :

$a_{n} = \frac{a_{1}(r^{n})}{r}$

In this example, we have $a_{1}$ = 36 (the first term in the sequence) and

r = $\frac{2}{3}$ (the rate in which the sequence is changing).

Knowing what the values for r and $a_{1}$ are, now we can solve.

$a_{n} = \frac{a_{1}(r^{n})}{r}$ = $\frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} }$ = 54 · $\frac{2}{3} ^{n}$

Therefore, the formula to find the nth term of the given sequence is

54 · $\frac{2}{3} ^{n}$

3 0

3 years ago

Will mark brainliest

vovikov84 [41]

(0,0)-->(0,0)
(3,-1)-->(9,-3)
(3,3)-->(9,9)

so what you will plug after the dilation will be the points on the right/
hope i help

3 0

3 years ago

Read 2 more answers

The graph of h(x) is shown. Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which

fgiga [73]

Answer:

x-intercept

The point at which the curve crosses the x-axis, so when y = 0.

From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)

y-intercept

The point at which the curve crosses the y-axis, so when x = 0.

From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)

Asymptote

A line which the curve gets infinitely close to, but never touches.

From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5

(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).

5 0

2 years ago

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2 5/8 ×3 1/7 What's the answer for this ?

nikdorinn [45]

Answer:

$8 \frac{1}{4}$

Step-by-step explanation:

Let us solve

$2 \frac{5}{8} \times 3 \frac{1}{7} \\ \frac{21}{8} \times \frac{22}{7} \\ \frac{462}{56} \\ \frac{462 \div 2}{56 \div 2} \\ \frac{231}{28} \\ \frac{231 \div 7}{28 \div 7} \\ \frac{33}{4} \\ 8 \frac{1}{4}$

hope this helps you.

Please let me know if you have another questions :-)

5 0

3 years ago

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