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poizon [28]
2 years ago
6

Points that don't belong to any line​

Mathematics
1 answer:
svetlana [45]2 years ago
3 0

Answer:

Noncollinear points

Step-by-step explanation:

Collinear points lie on the same line. Noncollinear points are the opposite.

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Solve for x x + 6=18
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X=12

This is because you subtract 6 from both sides to get the x isolated.

So x=18-6

x=12 :)
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Rational Exponents (See attachments)
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Step-by-step explanation:

6 0
3 years ago
A point p in the first quadrant lies on the parabola y=x^2. Express the coordinates of p as a function of the angle of inclinati
max2010maxim [7]

Answer:

  • The coordinates of the point p are:       (x,xtan\alpha )

                   

           

Explanation:

1. Name the angle of inclination of the line joining p to the origin α.

2. Find the relation between the coordinates of the point (x,y)

When you draw a line from the origin to the parabola, the intersection point, p(x,y) will have coordinates (x,y).

As per the definition of the tangent trigonometric ratio you have:

  • tan\alpha =\frac{y}{x}

From which you can clear y:

  • y=xtan\alpha =>(x,y)=(x,xtan\alpha )

Which is the expression of the coordinates of p as a function of the angle of inclination of the line joining p to the origin.

8 0
3 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
3 years ago
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