If the cost of 16 bar of chocolate costs $84. Find the cost of 28 bars of chocolate.

Mathematics

1 answer:

BlackZzzverrR [31]2 years ago

8 0

Answer:

16 bars=$84, meaning that one bar cost 5.25

28 bars=$147

You might be interested in

Please help!!! I need this done today!!

Kryger [21]

Answer:

1) distance travelled = 75mi

time taken = 3 hrs.

speed = distance/time

= 75/3 = 25 mi/hr.

now, if time = 1.6 hrs.

Distance = speed x time

= 25 x 1.6 = 40.0 mi

---------------------------------------------------------------------------------------------

2) earning for 8 hrs. of work = $120.

therefore, rate of earning per hr. = 120/8 = $15/hr.

so, earning in 11 hrs. = 15 x 11 = $165

8 0

3 years ago

Mark bought refreshments. Sandwiches were 2.50 each and bottles of water were $1.25 each. He spent $356.25 on a total of 180 ite

Over [174]

First you have to write the equation. in the scenario, use standard form.
Ax+By=C
plug the numbers in. A=2.50, B=1.25, and C is the total, 356.25. the 180 doesn't come in quite yet.
your equation is 2.50x+1.25y=356.25. now, since they only bought 180 items, you can't go past that.

I am sorry, but I am about to leave for school, and therefore do not have enough time to answer the last of your question. I hope the part I could answer has helped you.

7 0

3 years ago

CAN YOU HELP ME PLEASE!!

timama [110]

1. 20 cm by 20 cm by 6 cm
2. 40 cm by 30 cm by 2 cm
Hope this helps

8 0

3 years ago

The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.

Scrat [10]

Just did a specific one of these; let's do the general case.

The point nearest the origin is (a,b).

The line from the origin through the point is

$bx - ay = 0$

The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):

$ax + by = a^2 + b^2$