P(x, y) Q(x,y)
P(-2, -1) start at 0. Go to the left two squares, then go down 1 square. mark a point there
Q(2, 4) start at 0. Go to the right two squares, go up 4 squares. mark a point there.
connect two points
make a right triangle
Then use the pythereom


Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
Answer:
-12
Step-by-step explanation:
I am assuming that you want (f*g)(4), which is the product of f and g at x = 4.
If this is actually the case, then one way to evaluate (f*g)(4) is to find f(4) and g(4) separately and then multiply the results together. This gives us
f(4)*g(4) = (8 + 4)*(-4 + 3) = -12
Answer:
x = 0 , 1
Step-by-step explanation:
x² = x
x² - x = 0
x ( x-1 ) = 0
x=0 and x=1