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MissTica
2 years ago
7

A micron is 1x10 -6 How do you write that number and unit in standard form?

Mathematics
2 answers:
velikii [3]2 years ago
7 0

Answer:

If the answer is 1 times 10 then minus 6 the answer to this will be 4

But if the question is 1 times 10 to the power of -6 then the answer will be 1/1000000

Step-by-step explanation:

It depends on how you are setting up the problem

Look at what the question is asking and choose based on that

hope this helps

Ahat [919]2 years ago
5 0
-60
Just add however many 0s at the end u need:)
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Please i need some help on this question
Pachacha [2.7K]

Answer:

1) For 3 tickets, the cost is $12

2) For 5 tickets, the cost is $20

3) $28 can purchase 7 tickets

4) For 10 tickets, the cost is $40

Step-by-step explanation:

1) For 3 tickets

8 = 2

x = 3

(8 ÷ x) = (2 ÷ 3)

Cross multiply,

2x = 8 x 3

2x = 24

x = 24 ÷ 2

x = $12

Use the same principle for the other questions. Use X (or any other variable) to represent the missing value, I e. the value you are calculating.

I hope this helps.

7 0
2 years ago
Decrypt the word DKA if it was encrypted using an alphabetic Caesar shift cipher that starts with shift 5 (mapping A to F), and
pochemuha

Answer:

YET

Step-by-step explanation:

TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.

TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.

D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.

SO, D IS DECRYPTED AS Y

GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.

K IS THEN DECRYPTED AS

K = J - I - H - G - F - E

K IS DECRPYTED AS E

GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS

A = Z - Y - X - W - V - U - T.

THUS, DKA IS DECRYPTED AS YET

5 0
3 years ago
How much must be added to each of the three numbers 1, 11, and 23 so that together they form a geometric progression?
Sliva [168]

Answer:

49

Step-by-step explanation:

Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x

and

b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q

Express q:

q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}

Solve this equation. Cross multiply:

(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49

5 0
3 years ago
And engineer in blueprint calls for a 10.5 foot clearance from some pipes to the wall the pipes are currently 8.25 feet from the
tatuchka [14]

Answer:222

Step-by-step explanation:

add it

7 0
3 years ago
The diagram below shows a shaded parallelogram drawn inside a rectangle. Using Pythagoras, find the hypotenuse of triangle A and
Julli [10]

Answer: 5.9 cm for both triangles.

Step-by-step explanation:

Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:  

c^2 = a^2 + b^2  

Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.  

Replacing with the values given:  

c^2 = 3^2 + 5^2  

c^2 = 9+25

c^2 = 34

c = √34

c = 5.9 cm

Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.

Feel free to ask for more if needed or if you did not understand something.  

5 0
3 years ago
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