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4 years ago

9

PLEASE HELP ME!! Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quad

rilateral EFGH represents the actual walkway. ABCD is similar to EFGH. What is the total length, in feet, of the actual walkway?

1 answer:

statuscvo [17]4 years ago

3 0

Answer:

192 Feet

Step-by-step explanation:

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Subtraction:<br><br> 57 - 28 = ? Show how to solve it step by step.

OverLord2011 [107]

Answer:

29

Step-by-step explanation:

50 - 20 = 30

7 - 8 = -1

30 - 1 = 29

8 0

3 years ago

A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 200 feet. What is its area, in square feet?

yawa3891 [41]

Answer:19,600

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help... the question is confusing

ziro4ka [17]

$\bf \stackrel{line~J}{y+8=-(x-2)}\implies y+8=-x+2
\\\\\\
y=-x-6\implies y=\stackrel{slope}{-1}x-6$

now we know the slope of line J is -1.

a line perpendicular to J, will have a negative reciprocal slope, therefore,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -1\implies \cfrac{-1}{\underline{1}}\\\\
negative\implies +\cfrac{1}{{{ \underline{1}}}}\qquad reciprocal\implies + \cfrac{{{ \underline{1}}}}{1}\implies 1$

therefore, line K has a slope of 1, and passes through 3,4,

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
% (a,b)
&&(~{{ 3}} &,&{{ 4}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 1
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-4=1(x-3)\implies y-4=x-3
\\\\\\
y=x+1$

8 0

3 years ago

22÷1/5 (urgent) I need this

castortr0y [4]

Answer:

110

Step-by-step explanation:

easy matth to me

tip:22÷1/5 is 22x5

6 0

3 years ago

Read 2 more answers

JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.

Ahat [919]

Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

5 0

3 years ago