Question

I need this to be simplified

Answer 1

Answer:

$\frac{x+2}{3x-1}$

Explanation:

→ $\frac{(x^2-9)(x+2)}{(3x^2 +8x -3)(x-3)}$

→ $\frac{\left(x+3\right)\left(x-3\right)\left(x+2\right)}{\left(3x^2+8x-3\right)\left(x-3\right)}$

→ $\frac{\left(x+3\right)\left(x+2\right)}{3x^2+8x-3}$

→ $\frac{\left(x+3\right)\left(x+2\right)}{\left(3x-1\right)\left(x+3\right)}$

→ $\frac{x+2}{3x-1}$