(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
Answer:
0.02 or 2% = Beta
Step-by-step explanation:
Given that,
Risk-free rate = 7 percent
Expected return on the market = 10 percent
Expected return on Security J = 13 percent
Therefore, the beta of Security J is calculated as follows;
Expected return on Security J = Risk-free rate + Beta (Expected return on the market - Risk-free rate)
13 percent = 7 percent + Beta (10 percent - 7 percent)
0.13 - 0.07 = 0.03 Beta
0.06 = 0.03 Beta
0.06 ÷ 0.03 = Beta
0.02 or 2% = Beta
Answer:
C. cot theta
Step-by-step explanation:
(csc theta -cot theta )/(sec theta -1)
csc = 1/ sin
cot = cos / sin
sec = 1 / cos
Let x = theta
(1/ sin x -cos x / sin x )/(1/ cos x -1)
Getting a common denominator in the denominator and combining terms
(1- cos x)/ sinx / ( 1 - cos x) / cos x
(1- cosx) (1- cosx)
----------- ÷ ------------
sinx cos x
Copy dot flip
(1- cosx) cosx
----------- * ------------
sinx 1 -cos x
Cancel like terms
cos x / sin x
cos / sin = cot
cot x
cot theta
Answer:
Step-by-step explanation:
1). Equation of a line which has slope 'm' and y-intercept as 'b' is,
y = mx + b
If slope 'm' = 1 and y-intercept 'b' = -3
Equation of the line will be,
y = x - 3
x - y = 3
2). Equation of a line having slope 'm' and passing through a point (x', y') is,
y - y' = m(x - x')
If the slope 'm' = 1 and point is (-1, 2),
The the equation of the line will be,
y - 2 = 1(x + 1)
y = x + 1 + 2
y = x + 3
x - y = -3
3). Equation of a line passing through two points 
and 
will be,
If this line passes through (-2, 3) and (-3, 4),
y - 3 = -1(x + 2)
y = -x - 2 + 3
y = -x + 1
x + y = 1
Answer:
a. 20
b. 5
Step-by-step explanation:
The scale factor is 5 because 6×5=30
a. 4×5=20
b. 25÷5=5
