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NeX [460]
2 years ago
8

In triangle ABC, a-64, b-18, and c-63. Find the value of B.​

Mathematics
1 answer:
lys-0071 [83]2 years ago
5 0

Triangles are shapes with three sides and angles

The value of B is 16.3 degrees

<h3>How to determine the value of B</h3>

The given parameters are:

a = 64

b = 18

c = 63

Next, we apply the following cosine formula

b^2 = a^2 + c^2 - 2ac\ cos(B)

So, we have:

18^2 = 64^2 + 63^2 - 2 * 64 * 63 \ cos(B)

Evaluate the exponents

324 = 8065 - 8064\ cos(B)

Collect like terms

324 - 8065 = - 8064\ cos(B)

-7741 = - 8064\ cos(B)

Solve for cos (B)

\cos(B) =0.9599

Take the arccos of both sides

B =cos^{-1}(0.9599)B = 16.3

Hence, the value of B is 16.3 degrees

Read more about triangles at:

brainly.com/question/17972372

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Answer:

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Step-by-step explanation:

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Plugging in the known values of ∠K and ∠Y gives;

m∠KNY = 180° - (30° + 45°) = 105°

m∠KNY = 105°.

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3 years ago
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Step-by-step explanation:

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5 0
3 years ago
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Answer:
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3 years ago
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Step-by-step explanation:

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