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3 years ago

There are 14 pieces of chalk and 42 packages of

Mathematics

2 answers:

dem82 [27]3 years ago

7 0

Answer:

qjwjjwmwjwu 4f fsnfh the t4hhrnrhnn4

Phantasy [73]3 years ago

5 0

C.
14

……………………………………

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A number multiplied by 2 is no more than 12

Furkat [3]

Number must be smaller than 6
x<6

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3 years ago

Answer PLS

Zolol [24]

Answer:

yes, your score is good for a seventh grader.

keep it up and you can score more.

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2 years ago

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How do i solve 3x-8x=-40

balandron [24]

Answer:

The answer is 8 below is how you do it.

Step-by-step explanation:

first combine like terms 3x-8x

then you will have 5x

then do 40/5 and you will get x=8

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3 years ago

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Sore ABC sells 8 lbs of oranges for $6.00. Store XYZ sells 14lbs of oranges for $11.20. Which store is less expensive and by how

Pavel [41]

Answer:

Store ABC is less expensive by $0.05 per pound

Step-by-step explanation:

Find the cost per pound for each store.

1. Store ABC - divide $6 by 8lbs = .75 per pound

2. Store XYZ - divide $11.20 by 14 lbs = .80 per pound

Find the difference.

.80 - .75 = .05

5 0

3 years ago

How can I evaluate this question?

ohaa [14]

$\bf \left(x^2-\cfrac{2}{\sqrt{x}}+1 \right)(\sqrt[3]{x}+3x-4)\quad 
\begin{cases}
\frac{2}{\sqrt{x}}\implies \frac{2}{x^{\frac{1}{2}}}\implies 2x^{-\frac{1}{2}}\\\\
\sqrt[3]{x}\implies x^{\frac{1}{3}}
\end{cases}
\\\\\\
(x^2-2x^{-\frac{1}{2}}+1)(x^{\frac{1}{3}}+3x-4)$

$\bf \\\\\\
\begin{cases}
x^2\cdot x^{\frac{1}{3}}+3x^3-4x^2\\\\
-2x^{-\frac{1}{2}}\cdot x^{\frac{1}{3}}-2x^{-\frac{1}{2}}\cdot 3x+2x^{-\frac{1}{2}}\cdot 4\\\\
+x^{\frac{1}{3}}+3x-4
\end{cases}
\\\\\\ 
\begin{cases}
x^{2+\frac{1}{3}}+3x^3-4x^2\\\\
-2x^{-\frac{1}{2}+\frac{1}{3}}-6x^{-\frac{1}{2}+1}+8x^{-\frac{1}{2}}\\\\
+x^{\frac{1}{3}}+3x-4
\end{cases}$

$\bf x^{\frac{7}{3}}+3x^3-4x^2-2x^{-\frac{1}{6}}-6x^{\frac{1}{2}}+8x^{-\frac{1}{2}}+x^{\frac{1}{3}}+3x-4
\\\\\\
\sqrt[3]{x^7}+3x^3-4x^2-\cfrac{2}{x^{\frac{1}{6}}}-6\sqrt{x}+\cfrac{8}{x^{\frac{1}{2}}}+\sqrt[3]{x}+3x-4
\\\\\\
x^2\sqrt[3]{x}+3x^3-4x^2-\cfrac{2}{\sqrt[6]{x}}-6\sqrt{x}+\cfrac{8}{\sqrt{x}}+\sqrt[3]{x}+3x-4$

8 0

3 years ago