7 = b/11
11 × 7 = 77
Answer:
b = 7
Answer:
Step-by-step explanation:
- (x+y-z)²= 4xy
- (x+y-z)²- 4xy = 0
- (x+y-z)²-(2√x√y)² = 0
- (x+y-z-2√x√y)(x+y-z+2√x√y) =0
- [(√x-√y)²-z]*[(√x+√y)²-z]=0
- (√x-√y)²-z = 0 or (√x+√y)²-z = 0
We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²
so (x+y-z)²= 4xy
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
cot A =
, tanA =
, cscA =
, secA = 
Consider the right side

= 
= 
=
× sinAcosA ( cancel sinAcosA )
= cos²A - sin²A
= cos2A
= left side ⇒ verified
F(a)= -3a+2b
Hope this helps!