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3 years ago

Which is more,5 ounces or 1 pund

2 answers:

4 0

One pound is greater than five ounces because there are 16 ounces in a pound. 16 ounces are greater than 5 ounces
Hope this helps and don't forget to choose the brainliset answer!!!

mote1985 [20]3 years ago

3 0

1 pound is more
1 pound is 16 oz
and 16 oz is more than 5 oz

Hope this helps

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The next four digits in the number 0.3435363738394041 are

Vera_Pavlovna [14]

<h3>The pattern is 0.01+</h3>

<u>So the next 4 digits are:</u>

0.34353637383940414243

3 0

2 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST!!! 20 POINTS!!!!!

Leto [7]

Answer:

Step-by-step explanation:

When you plug this expression into the calc, you should get 14 as your answer.

8 0

2 years ago

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It is attached please help! Why is it c?

Sergeeva-Olga [200]

The answer is B.
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6 0

2 years ago

Mario is making dinner for 9 people.Mario buys 8 containers of soup.Each container is 18 oz if everyone gets the same amount of

Firdavs [7]

Answer:

16 fluid ounces

Step-by-step explanation:

Mario buys 8 containers of soup.

Each container has 18 fluid ounces.

In other words, there are a total of:

$8\times 18=144$

144 fluid ounces.

Each of the 9 people got the same amount of soup. In other words, divided equally, each person got:

$144/9=16$

16 fluid ounces of soup.

And we're done!

4 0

2 years ago

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Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation

evablogger [386]

Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)

$sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} \\ \\ \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} )=1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\ cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\$
$2cos(x)sin\frac{ \pi }{4} =1 \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2} \\ 2cos(x) \frac{ \sqrt{2} }{2} =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x) =1 \\ \sqrt{2} cos(x)=1 \\$
$cos(x)= \frac{1}{ \sqrt{2} } \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z$

6 0

2 years ago