16r^2+ 2r -4r
16r^2 - 2r
2r ( 8r -1)
The answer is 72.8. in order to solve this problem, you need to use the pythagorean theorem. the equation is c^2-b^2=a^2.
75^2-18^2=a^2
75 squared minutes 18 squared is 5301. then you need to find the square root of 5301.
the square root of 5301 is 72.8079666, rounding to 72.8.
Answer:
for(j = n; j > 0; j--)
System.out.print(\"*\");
Step-by-step explanation:
-A for loop is a repetition control structure.
-It allows the efficiency to write a loop that would otherwise be written a couple of times.
-The output is a single line comprising n asterisks,
-The number of asterisks printed will be equivalent to the n-value declared.
Answer:
For each of the three basic trig functions, (sin, cos, tan) there are three more which act as their reciprocals. (csc, sec, and cot respectively)
Reciprocals, of course, are flipped fractions. If you have some number x, the reciprocal can be expressed as .
An important property of reciprocals is that if you mutliply them together they will cancel out--take for example.
Since secӨ is literally defined as the reciprocal of cosӨ, it is evident that
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Step-by-step explanation:
