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topjm [15]
3 years ago
7

A girl throws a 2 kg rock with a net force of 6 N. What is the acceleration of the rock?

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0
Answer:
acceleration = 3 m/s²

Explanation:
From Newton's second law:
Force = mass * acceleration
We are given that:
Force = 6 Newton
mass = 2  kg

Substitute with the givens in the above equation to get the acceleration as follows:
Force = mass * acceleration
6 = 2 * acceleration
acceleration = 6 / 2 = 3 m/s²

Hope this helps :)

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Rachel tells Jonah that she can turn a square, but he won’t be able to tell that it was turned after she is finished turning it.
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ANSWER: it’s a square. All sides will look the same after turning because all sides LOOK THE SAME lol.
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3 years ago
Can you please help me on -6(7v-5)-3=3(v-6)
GalinKa [24]

Answer:

v = 1

Step-by-step explanation:

-6(7v - 5) - 3 = 3(v - 6)

distribute -6 into 7v - 5

-42v + 30 - 3 = 3(v - 6)

distribute 3 into v - 6

-42v + 30 - 3 = 3v - 18

add 30 and -3 together

-42v + 27 = 3v - 18

subtract 3v from both sides

-45v + 27 = -18

subtract 27 from both sides

-45v = -45

divide by -45 on both sides

v = 1

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4 years ago
What is the equation of the following line?<br><br> (-3,9)<br><br> (0,0)
elena55 [62]

Answer:

y=-3x

Step-by-step explanation:

8 0
2 years ago
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Find the inequality represented by the graph.
sweet-ann [11.9K]

Answer:

x > 3

Step-by-step explanation:

dotted line = > or <

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(Photo attached) Trig question. Please explain and thanks in advance! :)
nirvana33 [79]

Answer:

  0.2036

Step-by-step explanation:

u = arcsin(0.391) ≈ 23.016737°

tan(u/2) = tan(11.508368°)

tan(u/2) ≈ 0.2036

__

You can also use the trig identity ...

  tan(α/2) = sin(α)/(1+cos(α))

and you can find cos(u) as cos(arcsin(0.391)) ≈ 0.920391

or using the trig identity ...

  cos(α) = √(1 -sin²(α)) = √(1 -.152881) = √.847119

Then ...

  tan(u/2) = 0.391/(1 +√0.847119)

  tan(u/2) ≈ 0.2036

__

<em>Comment on the solution</em>

These problems are probably intended to have you think about and use the trig half-angle and double-angle formulas. Since you need a calculator anyway for the roots and the division, it makes a certain amount of sense to use it for inverse trig functions. Finding the angle and the appropriate function of it is a lot easier than messing with trig identities, IMO.

6 0
3 years ago
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