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3 years ago

A student applies 0.3 N of force to a computer mouse. The mouse slides .025 m. How much work did the student do on the mouse?

Mathematics

1 answer:

Kipish [7]3 years ago

8 0

Answer:

0.0075 N·m

Step-by-step explanation:

Work is the product of force and distance:

W = fd

W = (0.3 N)(0.025 m) = 0.0075 N·m

<em>Additional comment</em>

1 N·m = 1 J

Use the units you like. You could also write this in terms of millijoules: 7.5 mJ.

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The cost of membership at local country club is $125 per family member per month. Each family also has to pay $75 in service fee

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James creates the table shown to represent the function ƒ(x) = x2 + 8x + 12. Determine the zero(s) of the function.

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Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

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3 years ago

During the 2007 baseball season, Wade was up to bat 10 more times than

bearhunter [10]

Answer:

The number of times Ellis get to bat is 558.

Step-by-step explanation:

Here, let us assume the number of times Ellis bat = m

So, the number of times Dwight bat = 17 times fewer than Ellis

= m - 17

Also, number of times Wade got to bat = 10 more times than Dwight

= ( m- 17 )+ 10

Total number of bat times = 1650

So, the number of times ( Wade + Dwight + Ellis) bat together = 1650

⇒ ( m- 17 )+ 10 + (m - 17) + m = 1650

or, 3 m - 34 + 10 = 1650

or, 3 m = 1674

⇒ m = 1674/3 = 558 , or m = 558

Hence, the number of times Ellis get to bat = m = 558.

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4 years ago

Hello my name is juan and I new here are you able to be nice and give me a nice welcome greet

grigory [225]

Answer:

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Step-by-step explanation:

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4 years ago