<span>Step 1: 0.225 = 225⁄1000</span>
<span>Step 2: Simplify 225⁄1000 = 9⁄40</span><span> </span>
This equation is unsolvable.
x^2+8x+16=0
(x+4)^2+9=0
(x+4)^2= -9
anything to the power of whatever has to be greater than -1, it means it can be 0 or more but never a negative number. If it is a negative number, then it is false.
Answer:
H. 260
Step-by-step explanation:
We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.
14 tables * 14 students = total students
196 = total students ( for those fourteen tables)
Now we also know that sixteen students can sit on the rest of the cafeteria tables.
We need to find the number of tables can hold sixteen students.
To do this, we'll lead with a simple equation:
18 tables total - 14 tables = # of remaining tables
4 = # of remaining tables
Now we're going to do the same thing we did with the original tables:
4 tables * 16 students = total students
64 = total students
Finally, we add both of the tables max values together:
64 + 196 = 260
Answer: The answer is (a) sec A = 11 over 3.
Step-by-step explanation: Given that Cosine of an angle 'A' is 3 over 11,
i.e.,
And we need to find which one of the given four options is correct.
We have the following relations between cosine, secant and cosecant of an angle from trigonometry.
Therefore,
and
Thus, the correct option is (a) sec A = 11 over 3.
The domain { x | x = -5 , -3 , 1 , 2 , 6}
