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2 years ago

13

For what value of x does 625 - 5^6-2x?

1 answer:

alexdok [17]2 years ago

5 0

Answer:

x = 1

Step-by-step explanation:

$625 = {5}^{6 - 2x} \\ \\ \implies \: {5}^{4} = {5}^{6 - 2x} \\ \\ (bases \: are \: equal \: so \: \\ exponents \: will \: also \: be \: equal )\\ \\ \implies \: 4 = 6 - 2x \\ \\ \implies \: 2x = 6 - 4 \\ \\ \implies \: 2x = 2 \\ \\ \implies \: x = \frac{2}{2} \\ \\ \implies \: \huge \red{ \boxed{x =1}}\\ \\$

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alisha [4.7K]

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Answer:

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Step-by-step explanation:

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3 years ago

Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f

vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

$f(x)=ax^3+bx^2+cx+d$

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

$y = x^3 - x$

Equate y to 0

$x^3 - x = 0$

Expand

$x(x^2 - 1) = 0$

Express $x^2 - 1$ as difference of two squares

$x(x - 1)(x +1 ) = 0$

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For 2 x intercepts

$y = x^3 - x$

$y =(x-5)^2)(x+7)$

Equate y to 0

$(x-5)^2(x+7) = 0$

Expand

$(x-5)(x-5)(x+7) = 0$

<em>x= 5 or x = -7</em>

For 1 x intercept

$y = x^3$

Equate y to 0

$x^3 = 0$

Take cube roots of both sides

$x = 0$

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

$y = x^2 + x + 17$

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

$y = x^2- 6x + 9$

Equate y to 0

$x^2- 6x + 9 = 0$

Expand

$x^2 - 3x - 3x + 9 = 0$

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$x = 3$

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

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4 years ago

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andrew11 [14]

The number is 12.

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Hope I helped!

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3 years ago

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ZanzabumX [31]

Answer:

Step-by-step explanation:

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3 years ago