2 years ago

Number 1 is NOT proportional because when I cross multiply, I get 2 different products.Is this true or false.

1 answer:

6 0

Answer:

If you get two different products then you are doing it wrong, so false.

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Alenkasestr [34]

Answer:

hey

Step-by-step explanation:

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3 years ago

dem82 [27]

12 I’m pretty sure because you have x then 3 then 12

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3 years ago

Hunter-Best [27]

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3 years ago

miskamm [114]

I'm pretty sure it's 5.4

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4 years ago

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago