Simplify (8x2 − 1 2x3) − (7x3 − 3x2 1). −5x3 11x2 − 2 5x3 − 11x2 2 x3 2x2 x3 x3 − 2x2 − x3.

Mathematics

2 answers:

Harrizon [31]2 years ago

8 0

Answer:

-5x^3 +11x^2-2

(8x^2 − 1 + 2x^3) − (7x^3 − 3x^2 + 1)Distribute the minus sign(8x^2 − 1 + 2x^3) − 7x^3 + 3x^2 - 1I like to line them up vertically from largest to smallest2x^3 + 8x^2 − 1− 7x^3 + 3x^2 - 1------------------------------5x^3 +11x^2-2

correct me if im wrong

Komok [63]2 years ago

7 0

Answer:

-5x^3 +11x^2-2

Step-by-step explanation:

(8x^2 − 1 + 2x^3) − (7x^3 − 3x^2 + 1)

Distribute the minus sign

(8x^2 − 1 + 2x^3) − 7x^3 + 3x^2 - 1

I like to line them up vertically from largest to smallest

2x^3 + 8x^2 − 1

− 7x^3 + 3x^2 - 1

-----------------------------

-5x^3 +11x^2-2

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M(x) = 4x + 15; m(x) = 7

stealth61 [152]

Hi there! :)

$\huge\boxed{x = -2}$

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Find the value of "x" that would satisfy m(x) = 7:

4x + 15 = 7

Subtract 15 from both sides:

4x = -8

Divide both sides by 4:

x = -2.

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Two isosceles triangles have the same base length. the legs of one of the triangles are twice as long as the legs of the other.

Makovka662 [10]

An isosceles triangle is a type of triangle where 2 sides are equal.

Picture out 2 triangles with the same base length.
On the first triangle, its legs are twice the length of the legs of the second triangle.

To put it into variables, let:
B = the same base length of the two triangles
A = the length of one leg the smaller triangle
2A = the length of one leg of the bigger triangle

Given: Perimeter of smaller triangle = 23cm
Perimeter of bigger triangle = 43cm

Recall the formula for solving the perimeter of a triangle:
Perimeter = A + B + C

where, A, B, and C are the legs of the triangle

Since the triangle involved is an isosceles triangle, therefore, we can say that
Perimeter = 2A + B , 2 legs are equal ( A=C )

Substituting the given perimeter value to the formula.

23cm = 2A + B ⇒ equation 1 (smaller triangle)
43cm = 2(2A) + B ⇒ equation 2 (bigger triangle)

Simplifying equation 2.
43cm = 4A + B
(rearranging) B = 43cm - 4A ⇒ equation 3

Substituting equation 3 to equation 1:
(equation 1) 23cm = 2A + B
23cm = 2A + (43cm - 4A)
23cm = -2A + 43cm
2A = 43cm - 23cm
2A = 20cm ⇒ length of the leg of the bigger triangle
A = 10cm ⇒ length of the leg of the smaller triangle

To solve for the base length, just substitute the value of A to equation 3
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B = 43cm - 4(10cm)
B = 3 cm

Final Answer:

• For the smaller triangle, the length of the sides are 10cm, 10cm, and 3cm
• For the bigger triangle, the length of the sides are 20cm, 20cm, and 3cm

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3 years ago

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Andrej [43]

This rule shows how we transition the x-coordinate and y-coordinate when finding B'.

In this rule, it shows us what to add/subtract from the x-value and y-value in the coordinate. We can see that it wants us to subtract 5 from the x-value (based on the "x - 5") and that it wants us to add 9 to the y-value (based on the "y + 9"). Based on this information, we can find B':

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