Help solve for a????
2 answers:
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Answer:
y +8 = -4(x -8)
Step-by-step explanation:
You recognize that the given equation is in slope-intercept form:
y = mx + b
with m = 1/4 and b = 5.
A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...
-1/m = -1/(1/4) = -4
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . for slope m through point (h, k)
Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...
y +8 = -4(x -8)
Answer:
Step-by-step explanation:
Answer:
I have attached a picture of me solving the equation.
Now you must be wondering how I got the answer, well first simplify the expression in y = mx + b. Then graph it on demos. Do the same thing for the other expression. Pick any point that lies on the line. That is your solution to the equation.
The green line is the expression of 3x - 4y = 11. I simplify the equation in y = mx + b giving me y = 3/4x - 11/4.
The orange line is the expression of 3x + 2y = 2. I simplify the equation in y = mx + b giving me y = -3/2x + 1.
Hope this helps, thank you !!
