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stiv31 [10]
3 years ago
10

The function f(x) = x3 – 8x2 + x + 42 has zeros located at 7, –2, 3. Verify the zeros of f(x) and explain how you verified them.

Describe the end behavior of the function.
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

Step-by-step explanation:

At first you need to turn roots into factors and then multiply the

then you have

f(x) = a(x + 2)(x -5)^2

f(x) = a(x + 2)(x^2 - 10x + 25)

f(x) = a(x^3 - 8x^2 + 5x + 50)

You can use either synthetical or the factor

theorem

f(-2) = a(-8 - 8(4) + 5(-2) + 50) = a(0) = 0.. check, f

=-2

€(5) = a(125 - 8(25) + 5(5) + 50) = a(0) = 0 check, f

= 5 works

Then divide it to the the second multi

And you should get x^2 - 3x - 10 = (x - 5)(x + 2),

where the other two zeros are X =5 , and x=-2

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mixer [17]

well that took alot of guesses...

5 0
3 years ago
Can you find sets of positive integers that satisfy the following?
Hitman42 [59]

Answer:

{ 6 ,6 , 6, 7 , 10 } , { 5 , 6 , 6 , 8 , 10 }  ,  { 4 , 6 , 6 , 9 , 10 } , etc. (There's a lot more)

Explanation:

Mean of a set is equal to the terms added divided by the number of terms.

Median is the middle number when you order out the terms in the set in the increasing order from left to out.

Mode is the most occurring term.

Now, since the mean of five number  

{ v , w , x , y , z }  is  7 , we have:  v + w + x + y + z 5 = 7  => v + w + x + y + z = 35

Now, the middle term, the median, is 6.

Now we have:  

{ v , w , 6 , y, z }

Since the mode is 6, there has to be at least two 6.

There isn't enough limitations to have one answer.

For example, you could have this:

{ 4 , 5 , 6 , 6 , 14 }

The values add up to 35, the middle term is 6, and 6 is the most occurring.

You will find many other sets possible.

Step-by-step explanation:

Use this way to solve the rest.

7 0
3 years ago
Question
34kurt

Answer:

no I have no idea I justwant points

5 0
4 years ago
Read 2 more answers
Solve for x: |x − 2| + 10 = 12
raketka [301]
✯<span>Let's solve this equation step-by-step!
</span>✯<span>is the question you've asked us today:
|x − 2| + 10 = 12

</span>✯<span>Add -10 to both sides:
</span><span><span><span>|x−2|</span>+10</span>+−10</span>=<span>12+<span>−10
</span></span>
✯<span>Solve Absolute Value:
</span><span>|x−2|</span>=<span>2
</span>
✯We know either: 
<span>x−2=2 </span>or <span>x−2=<span>−<span>2
</span></span></span>
(Possibility 1) <span>x−2=2
</span>
(Add 2 to both sides) <span><span>x−2+2</span>=<span>2+2
</span></span>
x=<span>4
</span>
(Possibility 2) <span>x−2=<span>−2
</span></span>
(Add 2 to both sides) <span><span>x−2+2</span>=<span>−2+2</span></span>

x=<span>0
</span>
✯So since we have gotten x=4 and x=0 you answer shall be:

B. x=4 and x=0

✯I hope this helps!<span>✯</span>

3 0
3 years ago
Read 2 more answers
Anyone know and like to help? Thanks! :)
miv72 [106K]
2(p)
P^2
4+p(2)

Hope this helps
8 0
3 years ago
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