Answer:
<u>B</u><u>.</u><u> </u>
Step-by-step explanation:
We answer that before thank you
Distribute 7 to both n and 1
7(n + 1) = 7n + 7
5n + 7 = 7n + 7 - 2n
Combine like terms
5n + 7 = 7n - 2n + 7
5n + 7 = 5n + 7
If you want to solve for n, subtract 7 from both sides
5n + 7 (-7) = 5n + 7 (-7)
5n = 5n
then divide 5 from both sides
5n/5 = 5n/5
n = n
Effectively, this equation is <em>unsolvable</em>
hope this helps
Well I don't know !
Let's take a look and see:
The idea is that there could be more than one way
for a roll of the dice to land with the same number.
-- If the sum is from 1-4, you get the point.
There are 6 different ways for a roll of the dice to come up 1-4.
-- If the sum is from 5-8, Adam gets the point.
There are 20 different ways for a roll of the dice to come up 5-8.
-- If the sum is 9-12, Lana gets the point.
There are 10 different ways for a roll of the dice to come up 9-12.
-- The game is not fair to all three of you.
-- Lana has a distinct advantage over you.
-- Adam has a big advantage over Lana.
-- Adam has an even bigger advantage over you.
-- You are at a big disadvantage. (Notice that one of your
numbers ... 1 ... can never come up unless one of the dice
falls off of the table.)
_______________________________
Here's how to figure it:
Ways to roll a 2:
1 ... 1
Ways to roll a 3:
1 ... 2
2 ... 1
Ways to roll a 4:
1 ... 3
2 ... 2
3 ... 1
Ways to roll a 5:
1 ... 4
2 ... 3
3 ... 2
4 ... 1
Ways to roll a 6:
1 ... 5
2 ... 4
3 ... 3
4 ... 2
5 ... 1
Ways to roll a 7:
1 ... 6
2 ... 5
3 ... 4
4 ... 3
5 ... 2
6 ... 1
Ways to roll an 8:
2 ... 6
3 ... 5
4 ... 4
5 ... 3
6 ... 2
Ways to roll a 9:
3 ... 6
4 ... 5
5 ... 4
6 ... 3
Ways to roll a 10:
4 ... 6
5 ... 5
6 ... 4
Ways to roll 11:
5 ... 6
6 ... 5
Ways to roll 12:
6 ... 6
Answer:
This Is Science Not Math So Pls Dont Post Irrelevant Things To Maths
Step-by-step explanation:
Thank you for letting me know lol. this wasnt a question
