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Dmitrij [34]
3 years ago
13

1) Find the general solution to the following differential equation x^3•y’- y = 0

Mathematics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

y(x) = c_1 e^(-1/(2 x^2))

Step-by-step explanation:

Solve the separable equation x^3 (dy(x))/(dx) - y(x) = 0:

Solve for (dy(x))/(dx):

(dy(x))/(dx) = y(x)/x^3

Divide both sides by y(x):

((dy(x))/(dx))/y(x) = 1/x^3

Integrate both sides with respect to x:

integral((dy(x))/(dx))/y(x) dx = integral1/x^3 dx

Evaluate the integrals:

log(y(x)) = -1/(2 x^2) + c_1, where c_1 is an arbitrary constant.

Solve for y(x):

y(x) = e^(-1/(2 x^2) + c_1)

Simplify the arbitrary constants:

Answer:  y(x) = c_1 e^(-1/(2 x^2))

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Step-by-step explanation:

Let the quadratic function be

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f(x)=1(x+4)²-1

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4 0
3 years ago
the lighting for a billboard is provided by solar energy. if 4 energy panels generate 10 watts of power, how many panels are nee
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3 years ago
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SIZIF [17.4K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Evaluate C(7, 7).
Romashka [77]
If you're seeing these problems as part of your study of statistics, you should know that
  C(n, k) = n!/(k!×(n-k)!)
where the "!" indicates the factorial, the product of all positive integers less than or equal to the given one.

Then C(7, 7) = 7!/(7!×0!) = 1/0!
You are supposed to know also that 0! ≡ 1, so C(7, 7) = 1.

This is the number of ways you can choose 7 objects from a pool of 7 objects without regard to order. (You can do it one (1) way: choose all of them.)

The appropriate choice is ...
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7 0
3 years ago
Read 2 more answers
Inequality to x2 < 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
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