Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Answer:
No
Step-by-step explanation:
Mitochondria is the powerhouse of the cell
Measures change in price levels of market s
The range is the output of the function, and there are many ways to find it and write it. Let's find it first by plugging in all the domain values (domain means input) into the function:
We have all of our values. We can either write the range as:
{
}
or, subtract the smallest value from the largest one:
So, there are those ways to write it, there are more, but I think you should stick with the first way because that's how the problem was presented to you. If you have any questions, hmu!
