I need help to figure this out?can someone help me?
1 answer:
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For x-intercepts "b" and "c", a quadratic can be written as
y = a(x -b)(x -c)
You know the x-intercepts, so you can write the equation as
y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices
Substituting (x, y) = (-1, 2), you have
2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
-2/4 = a = -1/2 . . . . . corresponds to the third answer choice
The appropriate selection is
y = -1/2 (x + 2)(x - 3)
y = a(x -b)(x -c)
You know the x-intercepts, so you can write the equation as
y = a(x +2)(x -3) . . . . . . eliminates the first two answer choices
Substituting (x, y) = (-1, 2), you have
2 = a(-1+2)(-1-3) = -4a
Then dividing by -4 gives
-2/4 = a = -1/2 . . . . . corresponds to the third answer choice
The appropriate selection is
y = -1/2 (x + 2)(x - 3)
Answer:
Step-by-step explanation:
The complete question in the attached figure
we know that
When two lines are crossed by another line (transversal), a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal, are called <em><u>Alternate Interior Angles</u></em>.
When the two lines being crossed are Parallel Lines the Alternate Interior Angles are congruent
In this problem
---> by alternate interior angles
we have
therefore
