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dsp73
2 years ago
7

Find three consecutive Odd numbers whose sumis at most 126​

Mathematics
2 answers:
bixtya [17]2 years ago
6 0

Answer:

The 3 numbers are <em>41, 42</em>, and <em>43</em>

Step-by-step explanation:

Bumek [7]2 years ago
4 0

Answer:

41+42+43=126

Step-by-step explanation:

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WILL MARK BRAINLY. 20pts
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6 0
3 years ago
Simplify the expression shown below: (a^3b^12c^2)^2(a^5c^2)^3(b^5c^4)^0
NemiM [27]
= a^21b^24c^10 
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3 years ago
Why is it sometimes best to make a phone call or personal contact when conveying sensitive information?
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3 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
1 year ago
A certain chalkboard manufacturer determines that their largest blackboard model has a mean length of 5.00 m and a standard devi
Igoryamba

Answer:

23 chalkboards

Step-by-step explanation:

Given:

Mean length = 5 m

Standard deviation = 0.01

Number of units ordered = 1000

Now,

The z factor = \frac{\textup{x - Mean}}{\textup{standard deviation}}

or

The z factor = \frac{\textup{4.98 - 5}}{\textup{0.01}}

or

Z = - 2

Now, the Probability P( length < 4.98 )

Also, From z table the p-value = 0.0228

therefore,

P( length < 4.98 ) = 0.0228

Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.

7 0
3 years ago
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