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Dennis_Churaev [7]
2 years ago
15

At a certain high school, 15 students play stringed instruments and

Mathematics
1 answer:
Aleks [24]2 years ago
5 0

Answer:

<em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N(A \cup B)' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N(A \cup B)' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

N(A\cap B) =0

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0

So, <em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

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A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company
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Step-by-step explanation:

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