The answer is 7/10 but if you want it in decimal for it is 0.7
To determine change in Gibbs Free Energy, we use the equation
ΔG = ΔG° + RT ln Q
where ΔG is the change in free energy at temperature T
ΔG° is the free energy at standard temperature
R is the universal gas constant
T is the temperature of the system
Q is the reaction quotient
First, we determine the reaction quotient. It is the ratio of the concentration or partial pressure of the products and the reactants. For this case, we do as follow:
<span>P2(g) + 3 Cl2(g) -> 2 PCl3(g)
</span>
<span>Q = P(PCl3) ^2 / (P(P2)(P(Cl2 ^ 3)))
</span>Q = (0.65 atm)^2 / (1.5 atm) (1.6 atm)^3
Q = 0.0688
Substituting to the equation for free energy,
ΔG = ΔG° + RT ln Q
ΔG = -33300 J/mol + (8.314 J/mol-K)(298 K) ln 0.0688
ΔG = -39931.35 J/mol
I would go with false but idk
Answer:
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6
Bromocresol green, color change from pH = 4.0 to 5.6
Explanation:
The equation for the reaction is :
concentration of = 10%
10 g of in 100 ml solution
molar mass = 45.08 g/mol
number of moles = 10 / 45.08
= 0.222 mol
Molarity of
= 2.22 M
number of moles of in 20 mL can be determined as:
Concentration of
= 2.22 M
Similarly, The pKa Value of is given as 10.75
pKb value will be: 14 - pKa
= 14 - 10.75
= 3.25
the pH value at equivalence point is,
Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6
Answer:
The perimeter of a Rectangle P= 2(l + b)
Area of a Rectangle A = l × b