Answer:
Gas
Explanation:
Because Crude oil can usually be found in the ground as a liquid and in the air is gas can be kerosene.
Answer:
General Formulas and Concepts:
<u>Chemistry - Gas Laws</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
- Charles' Law:
Explanation:
<u>Step 1: Define</u>
Initial Volume: 5.0 L H₂ gas
Initial Temp: 273 K
Final Temp: 985 K
Final Volume: ?
<u>Step 2: Solve for new volume</u>
- Substitute:
- Cross-multiply:
- Multiply:
- Isolate <em>x</em>:
- Rewrite:
<u>Step 3: Check</u>
<em>We are given 2 sig figs as the smallest. Follow sig fig rules and round.</em>
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Answer:
Main job of golgi bodies is to sort and package proteins and other substances in a plant cell.
Explanation:
Golgi bodies are also called post office of the cell because it modify and distribute proteins for the cell. First, proteins are made in the organelle of the cell i. e. endoplasmic reticulum. From here, it is send to the Golgi apparatus for modification. Golgi bodies add some special structures with the protein and this protein leaves golgi bodies which is used by the cell where it is needed.
Answer:
Non-zero digits are always significant
0.003 moles of NaOH was used in the titration.
<h3>What is titration?</h3>
The concentration of an identified analyte can be found using a simple laboratory technique called titration. As a standard solution with a given concentration and volume, a reagent known as the titrant or titrator is created.
By using a solution with a known concentration to measure the concentration of an unknown solution, this process is known as titration. To a known volume of the analyte (the unknown solution), the titrant (the known solution) is typically added from a buret until the reaction is finished. To ascertain the unknown concentration of an identifiable analyte, titration, commonly referred to as titrimetry, is a widely used quantitative laboratory analytical technique (Medwick and Kirschner, 2010). Volume measurements are a crucial component of titration
Concentration in mol/dm3 =
Amount of solution mol
= concentration in mol/dm3 × volume in dm3
Amount of sodium hydroxide
= 0.100 × 0.0250
= 0.00250 mol
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