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Elanso [62]
2 years ago
11

A bullet is fired into the air with an initial velocity of 881 feet per second at an angle of 55° from the horizontal. Find the

magnitudes of the horizontal and vertical vector components of the velocity vector V, namely Vx and Vy, respectively. (Round your answers to one decimal place.)
Mathematics
1 answer:
snow_lady [41]2 years ago
8 0

The horizontal and vertical vector components of the velocity vector V, namely Vx and Vy are; 505.32 ft/s and 721.57 ft/s respectively

<h3>Horizontal and Vertical components of vectors</h3>

For ease of computation since vectors have magnitude and direction; they are resolved into horizontal and vertical components.

By convention, the horizontal, Vx and vertical components, Vy are as follows;

  • Vx = V cos π
  • Vy = V sin π

where π = angle of inclination to the horizontal.

Hence,

  • Vx = 881 × cos55° = 505.32 ft/s

  • Vy = 881 × sin55° = 721.57 ft/s

Read more on vectors and direction;

brainly.com/question/4417902

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<h3>Simplifying Logarithms</h3>

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Learn more on Simplifying logarithms here: brainly.com/question/17851187

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