Question

The square ABCD has side length 20cm. E is the midpoint.

Answer 1

Answer:

22.4 cm

Step-by-step explanation:

AB = 20 cm, BE = (1/2) * 20 cm = 10 cm

By pythagorous theorem,

AE = $\sqrt{20^{2} + 10^{2}}$ cm = $10$$\sqrt{3}$ cm = 22.4 cm

Answer 2

The length of AE is 22.36 cm

Step-by-step explanation:

Given,

In the fig: AB = 20 cm

E is the mid point of BC.

So, BE = 10 cm

To find the length of AD

Here,

ΔABE is a right angle triangle.

So,

$AB^{2} +BE^{2} =AE^{2}$

Now, putting the values of AB and BE we get,

$20^{2} +10^{2} =AE^{2}$

or, $AE^{2}$ = 400+100

or, AE = $\sqrt{500}$ = 10$\sqrt{5}$

= 10×2.236 = 22.36 (approx)