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White raven [17]
3 years ago
7

3x - y = 2 and 2x + y = 4 X= y =

Mathematics
2 answers:
AveGali [126]3 years ago
6 0

Answer:

.The solution is

x = 1.2

y = 1.6

Juliette [100K]3 years ago
6 0

Answer:

x=6/5

y= 8/5

Step-by-step explanation:

This is a system of equations, and you can solve it in different methods.

The method I chose was substitution

If you rearrange the 1st equation, you find that y=3x-2

You can substitute that into the second equation

This is how it will look like:

2x+3x-2=4

Now you can simplify the equation to 5x-2=4

Bring the 2 to the other side

Now the equation looks like this:

5x=6 ===> x=6/5

Now substitute this value in the first equation.

This is how it will look like:

3(6/5)-y=2

Now you can simplify the equation to 18/5-y=2

Bring the 2 to the other side and do the same for y

The equation will look like this:

18/5-2=y ===> y=18/5-2

Now subtract

You will get:
y= 8/5

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Find the value of x so that the function has the given value. <br> q(x)=12x−3; q(x)=−4
Anna [14]

Answer:

-  \frac{1}{ 12}

Step-by-step explanation:

since q(x)=-4

substitute

hence

-4=12x-3

take -3 to the other side where it becomes positive

therefore

-1=12x

divide by 12

you will get the above answer

5 0
3 years ago
How to find the equation of vertical and horizontal asymptotes?
amm1812
Please find some specific examples of functions for which you want to find vert. or horiz. asy. and their equations.  This is a broad topic.

Very generally, vert. asy. connect only to rational functions; if the function becomes undef. at any particular x-value, that x-value, written as x = c, is the equation of one vertical asy.

Very generally, horiz. asy. pertain to the behavior of functions as x grows increasingly large (and so are often associated with rational functions).  To find them, we take limits of the functions, letting x grow large hypothetically, and see what happens to the function.  Very often you end up with the equation of a horiz. line, your horiz. asy., which the graph usually (but not always) does not cross.

5 0
3 years ago
1.) Peggy walks at a rate of 2 miles per hour and jogs at a rate of 4 miles per hour. She walked and jogged 3.4 miles in 1.2 hou
Pepsi [2]
1.

<span><span>time she spent walking = T
</span><span>
</span></span>

time she spent jogging = 1.2 - T

<span>
<span>
</span></span>

<span><span>2T + 4(1.2 - T) = 3.4
</span><span>
</span></span>

<span><span>2T + 4.8 - 4T = 3.4
</span><span>
</span></span>

<span><span>2T - 4T = 3.4 - 4.8
</span><span>
</span></span>

- 2T = - 1.4

T = -1.4—2 = 0.7 hours = 42 minutes

Time she spent jogging = 1.2-0.7 = 0.5 hours = 30 minutes

2.

Against wind :2400 miles in 10 hours

With wind : 2400 miles in 8 hours

Speed of plane = x

Speed of wind = y

 

t=d/r

 

against the wind speed x-y mph

with the wind x=y mph

 

2400/(x-y)=10

2400 = 10x-10y

240 =x-y eq.1

2400/x+y=8

2400 = 8x+8y

300 = x+y eq 2

Add eq1 & eq 2 = 740 = 2x

X = 740/2 = 370 mph for plane

 

300 = 370 +y

Y = 370-300 = 70 mph wind speed


6 0
3 years ago
In a football game, the home team scored 1 touchdown and one extra point during every quarter. How many points did the home team
ratelena [41]

Answer:

28 points

Step-by-step explanation:

A touch down is 6 points and an extra point is 1 point

There are 4 quarters

6+1 = 7

4 quarters

4*7 = 28

They scored 28 points

3 0
3 years ago
Sean spend 15 more minutes than faith on algebra homework. The two students spent 55 minutes in all. How much time did faith spe
Paraphin [41]
Gotcha.

We know Sean spent 15 more minutes than Faith.

So, we know this to be true:


Sean = 15 + Faith


We also know that Sean and Faith spent a TOTAL time of 55 minutes on homework.

So, we have this:

Sean + Faith = 55


We can solve for Faith's time spent in homework now since we have two equations.


Here are the two equations we have:

Sean = 15 + Faith

Sean + Faith = 55

To make solving for Faith easier, I'm going to rearrange the second equation to this:

55 = Sean + Faith


Now, we solve the problem.


Sean = 15 + Faith

55 = Sean + Faith

We know what Sean is, he is 15 + Faith.

So, we can plug in 15 + Faith into Sean in the second equation.


55 = 15 + Faith + Faith

Simplify:


55 = 15 + 2Faith

55 - 15 = 15 - 15 + 2Faith

(I subtracted 15 from both sides)

40 = 2Faith

Now, divide by 2 on both sides to get Faith's time.

40 ÷ 2 = 2Faith ÷ 2

20 = Faith



If you have any questions or comments then please post them. Otherwise, good luck, and I hope this was useful!
3 0
3 years ago
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