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Evgen [1.6K]
3 years ago
10

How do I solve to get the answer for: 2t + 8 ≥ −4(t + 1)

Mathematics
1 answer:
Rzqust [24]3 years ago
4 0
2t + 8 ≥ -4t - 4
2t+4t ≥ -8-4
6t ≥-12
t ≥ -12/6
t ≥ -2
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Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|. The valu
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Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x  sufficiently close to 9.

C  f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2  Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

Answer:

1

   The correct option is  D

2

    The correct option is   A

Step-by-step explanation:

Generally a a limit function  \lim_{n \to x }  f(x) = L

Tell us that as n tends toward x the values of  f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

  Yes it is possible for  lim x → 8 f(x) = 9.  to be true and  f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

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Step-by step explanation:

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