This question is really hard
First we must set up the problem
(n)+(n+1)+(n+2)=8
we are given
Jimmy is trying to escape Jane
For finding total distance , we will find distances and then add them
He runs 12 km/hr for 5 minutes
First distance:
speed =12 kh/hr
time=5 minutes
we can change into hour
![t=\frac{5}{60}hr](https://tex.z-dn.net/?f=%20t%3D%5Cfrac%7B5%7D%7B60%7Dhr%20)
![d_1=s*t](https://tex.z-dn.net/?f=%20d_1%3Ds%2At%20)
now, we can plug values
![d_1=12*\frac{5}{60}](https://tex.z-dn.net/?f=%20d_1%3D12%2A%5Cfrac%7B5%7D%7B60%7D%20)
![d_1=1](https://tex.z-dn.net/?f=%20d_1%3D1%20)
second distance:
speed =17 kh/hr
time=8 minutes
we can change into hour
![t=\frac{8}{60}hr](https://tex.z-dn.net/?f=%20t%3D%5Cfrac%7B8%7D%7B60%7Dhr%20)
![d_2=s*t](https://tex.z-dn.net/?f=%20d_2%3Ds%2At%20)
now, we can plug values
![d_2=17*\frac{8}{60}](https://tex.z-dn.net/?f=%20d_2%3D17%2A%5Cfrac%7B8%7D%7B60%7D%20)
![d_2=2.26667](https://tex.z-dn.net/?f=%20d_2%3D2.26667%20)
third distance:
speed =6 kh/hr
time=2 minutes
we can change into hour
![t=\frac{2}{60}hr](https://tex.z-dn.net/?f=%20t%3D%5Cfrac%7B2%7D%7B60%7Dhr%20)
![d_2=s*t](https://tex.z-dn.net/?f=%20d_2%3Ds%2At%20)
now, we can plug values
![d_3=6*\frac{2}{60}](https://tex.z-dn.net/?f=%20d_3%3D6%2A%5Cfrac%7B2%7D%7B60%7D%20)
![d_3=0.2](https://tex.z-dn.net/?f=%20d_3%3D0.2%20)
now, we can find total distance
![d=d_1+d_2+d_3](https://tex.z-dn.net/?f=%20d%3Dd_1%2Bd_2%2Bd_3%20)
![d=1+2.26667+0.2](https://tex.z-dn.net/?f=%20d%3D1%2B2.26667%2B0.2%20)
![d=3.46667](https://tex.z-dn.net/?f=%20d%3D3.46667%20)
so,
total distance is 3.46667 km...........Answer
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
Answer:
-9
Step-by-step explanation:
eq.of line is
y+6=(3+6)/(4-1) ×(x-1)
y+6=3(x-1)
y+6=3x-3
y=3x-3-6
y=3x-9