The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
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Hey there!
There are 2.20462 pounds in a kilogram
Answer:
Option b. Two solutions
Step-by-step explanation:
In order to find how many real number solutions the equation has we have to solve it
Given equation: -4x² + 10x + 6 = 0
taking 2 common from the equation
2(-2x² + 5x + 3) = 0
-2x² + 5x + 3 = 0
taking minus sign common from the above equation
2x² - 5x - 3 = 0
We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²
2x² - 6x + x - 3 = 0
taking common above
2x(x-3) + 1(x-3) = 0
taking (x-3) common
(2x+1)(x-3) = 0
2x + 1 = 0
2x = -1
x = 
x - 3 = 0; x = 3
the solutions are

Both values are real numbers, therefore correct option is b
<span>it divides two sides of a triangle equally. The midpoint of a side divides the side into two equal segments.</span>
It should go like this:
(4z + 3) (3z - 4) / (3z - 4) (z + 2)
Then you just cancel out (3z -4) and (3z -4), and the final simplified form of this polynomial is:
(4z +3) / (z + 2)