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amm1812
2 years ago
11

PLS PLS PLS HELP I HAVE 2 TESTS DUE BY MIDNIGHT LOLZ ​

Mathematics
2 answers:
sveticcg [70]2 years ago
8 0
The initial value is 3)
cricket20 [7]2 years ago
4 0

Answer:

7

Step-by-step explanation:

The graph is moving up by 3 units and right by 7 units. The 1st point and 2nd point are 7 units apart, which is where I got my answer.

You might be interested in
The solution to the equation (2/3)x - 4 = 6 is x = -3
castortr0y [4]

yes

2/3 (-3) -4 = 6

2--4 = 6

6= 6

8 0
4 years ago
Please help me w this question!! I’m so confused!!
expeople1 [14]

Answer:

coefficient is 128 and exponent is 8

Step-by-step explanation:

8 0
3 years ago
Factorise 9w² - 100<br><br><br>​
ohaa [14]

Answer:

9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10).

Step-by-step explanation:

Fact:

\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}.

In other words, (a^{2} - b^{2}), the difference of two squares in the form a^{2} and b^{2}, could be factorized into (a - b)\, (a + b).

In this question, the expression (9\, w^{2} - 100) is the difference between two terms: 9\, w^{2} and 100.

  • 9\, w^{2} is the square of 3\, w. That is: (3\, w)^{2} = 9\, w^{2}.
  • On the other hand, 10^{2} = 100.

Hence:

9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}.

Apply the fact that a^{2} - b^{2} = (a - b) \, (a + b) to factorize this expression. (In this case, a = 3\, w whereas b = 10.)

\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}.

8 0
3 years ago
18s -17s+1=20 solve for s
liubo4ka [24]

Answer:

s=19

Step-by-step explanation:

18s-17s+1=20

s+1=20

s=20-1

s=19

6 0
4 years ago
Read 2 more answers
The imaginary coefficient of 18 + 15i is?
kykrilka [37]

Answer:

I bc it has an invisible 1 at the side

6 0
3 years ago
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