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mr Goodwill [35]
3 years ago
8

Which is an equation of the line through (-1, -4) and parallel to the line 3x + 7 = 5

Mathematics
1 answer:
ehidna [41]3 years ago
3 0
Your original equation has no y-variable. It results in x = -2/3 when you solve for x which is a vertical line. Thus, if you want a line parallel to this that goes through point (- 1, - 4), you just set x equal to the x-value in that ordered pair.

Your parallel line is x = - 1. 
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Answer:

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Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
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Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

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r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

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