Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
First thing is that you need to find the diagonal of the rectangle
but remember is it a horizontal rectangle.
So let's start it :)
d= √6²+3²
d= √36+9
d= √54
d= 6.7082
But wait.. we are not done yet
We need to solve KT
we have 6.7082 which is the base and we have SL=4 which is the height
so with this 2 information we can find KT
KT is the hypotenuse because when you draw the line from K to T you'll see that it is the longest line.
Use the hypotenuse formula which is
C = √a²+b²
Now replace C by KT since we are solving for KT instead of C. Got it ?:)
KT= √6.7080²+4²
KT= 7.81
I do it with decimals so it might be little bit confusing to you but I think you can solve that different ways :)
Well I hope that's help and if not I am so sorry.
Answer:yes, its correct
Step-by-step explanation:
20 women because you’d multiply the 6 by 5 to get 30 and then the 4 by 5 to get 20
Set the equation inside the absolute value brackets equal to 12 and -12, so you will end up with two answers.
7x+2=12 gives you 10/7
7x+2=-12 gives you -2.
So your answers are 10/7 and -2
