Ask question

Ask question

All categories

2 years ago

10

Amrita bought a new delivery van for $32,500. The value of this van depreciates at a rate of 12% each year. Write a function f(x

) to model the value of the van after x years of ownership.

1 answer:

Step2247 [10]2 years ago

4 0

Answer:

3900

Step-by-step explanation:

12/100 x 32,500/1

=3900

the ownership after year will be 3900

You might be interested in

Can Somebody Help Me Please?

nikdorinn [45]

Answer:

28 (length' unit)²

Step-by-step explanation:

the area of all A rectangle is 4*8 =32
The area of the missing portion of the rectangle is equal to the area of the triangle ½*(2)*(4)=4
the area of this shape equal to

the area of all A rectangle - The area of the missing portion of the rectangle = 32 - 4 = 28 (length' unit)²

4 0

2 years ago

What's 5/6 divided by 2

natali 33 [55]

5/6÷2/1
=5/6×1/2
=5/12 i hope this helps

7 0

2 years ago

18. Describe how to plot point A(-6, 2) on a coordinate plane.

Setler79 [48]

Answer:

To plot point A, you would count over to the left six places on the x-axis. Then, count up two places on the y-axis.

8 0

2 years ago

Help ASAP PLZZZZZZ I really need the answer

Kitty [74]

The last one because a perpendicular triangle would be drawn from the vertice to the bottom.

3 0

2 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

2 years ago