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weqwewe [10]
3 years ago
11

How fast was a driver going if the car left skid marks that were 48 feet long on dry concrete? (The coefficient of friction is 1

.02)?
A) 31 mph
B) 38 mph
C) 49 mph
D) 73 mph
Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

B) 38 mph

Step-by-step explanation:

s = √(30df)

s is the speed the car was traveling (in mph)

d is the distance the car skidded (in feet)

f is the coefficient of friction

s = √(30 x 48 x 1.02)

s = 38.32492661... = 38

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