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gizmo_the_mogwai [7]
3 years ago
6

Divide. Write your answer as a decimal. 4.95 = 0.18 = 1

Mathematics
2 answers:
Airida [17]3 years ago
5 0
4.95 divided by 0.18 is 27.5
Shtirlitz [24]3 years ago
4 0

Answer:

21.33 is your quotient in decodemal

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Kenny's charges $8 per hour to babysit he wants to figure out how much money do you earn in a week which variable is needed to c
Korolek [52]

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H

Step-by-step explanation:

The amount of hours he has worked would be x 8$

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True or false, the following two triangles are congruent by HL. <br><br> A.) False<br> B.) True
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The answer is for this question is true
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3 years ago
Solve the system of equations.<br> 2x-15y=6<br> x-6y=-1
Irina18 [472]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Find the following Euler Totients using Euler’s Theorem, as explained on p.409 of the text (10 points each): a.ϕ(13) b.ϕ(81) c.ϕ
ad-work [718]

(a) \varphi(13)=12 since 13 is prime.

(b) 81=3^4, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so \varphi(81)=54.

(c) 100=2^2\cdot5^2; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with \varphi(100)=100-60=40.

(d) 102=2\cdot3\cdot17; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so \varphi(102)=102-70=32.

4 0
4 years ago
Find the volume of the composite solid. Round your answer to the nearest tenth.​
amm1812

Answer:

Volume of the Figure =825.38m^3

Step-by-step explanation:

Volume of the figure = Volume of the Upper cone+Volume of the lower cone

Volume of a cone = \pi *r^2*\frac{h}{3}

Volume of the Upper Cone with  

height=12m

radius=6m

                       3.14*6*6*\frac{12}{3}

                        =3.14*6*6*4\\\\=3.14*36*4\\\\=3.14*144\\\\=147.14m^3

Volume of the Lower cone with radius=6m and height=18m

                            =3.14*6*6*\frac{18}{3} \\\\=3.14*6*6*6\\\\=3.14*36*6\\\\=3.14*216\\\\=678.24m^3

Volume of the Whole Figure =   147.14+678.24

Volume of the Figure  =825.38m^3

4 0
3 years ago
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