Osmosis is the net movement of water molecules through a semi-permeable memberane from a region of higher water potential to a region of lower water potential.
so in the first case, since 10% of sucrose solution has a lower water potential than the pure water, so water molecules will flow into the sac, causing the sac to increase in volume. note that sucrose molecules can't diffuse out since there's a semi-permeable membrane.
in the question, I'm not 100% sure what the "sac solution" is meant by, but I guess it's the solution inside the sac
so here if the sac sucrose is 20%, the concentration of water is larger in difference than the first time, so osmosis rate will increase.
but if the "sac solution" is meant by replacing the water of the first case, then the sac inside would have a higher water potential, as the sucrose concentration is more diluted. then the water molecules will flow from the sac back to the beaker or whatever container it is.
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Answer:
The correct answer is Introspection
Explanation:
From the given question, from the history of psychology, we can asses Dave's claim using what is called Introspection
Introspection refers to the training of participants to report elements of specific sensory experiences.
Introspection is also the scrutiny of one's personal feelings and conscious thoughts. In psychology, the process of introspection deals with exclusively on observation of one's mental state, while in the context of spirituality it may be called the examination of one's soul.
Answer:
1) The angle would be 150 degrees
a) coordinates would be ( 
, 
)
b) Trigonometric ratios:
sin:
cos:
tan: 
csc: 2,
sec: 
cot: 
Explanation:
simplifys to 
which has a reference angle of 
. We can take the coordinates of and make the x value negative to find the correct coordiantes. Then, using those coordinates, plug the into the trigonomic equations.
For example, sin in opposite/hypotenuse. So sin = 1/2 divided by 1. Then you can find the rest of the equations that way.
cos= adjacent/hypotenuse
tan= sin/cos
csc= hypotenuse/opposite
sec= hypotenuse/adjacent
cot= cos/sin
