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s2008m [1.1K]
3 years ago
10

SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R

eference have been imported where appropriate. Unless otherwise noted in the question, assume that parameters in method calls are not null and that methods are called only when their preconditions are satisfied. In writing solutions for each question, you may use any of the accessible methods that are listed in classes defined in that question. Writing significant amounts of code that can be replaced by a call to one of these methods will not receive full credit. A mathematical sequence is an ordered list of numbers. This question involves a sequence called a hailstone sequence. Ifnis the value of a term in the sequence, then the following rules are used to find the next term, if one exists. If n is 1, the sequence terminates. If n is even, then the next term is n2. If n is odd, then the next term is 3n 1. For this question, assume that when the rules are applied, the sequence will eventually terminate with the termn

Computers and Technology
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

Kindly check the attached image below for the code output.

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A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t
Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

   class Program

   { \\ starting the main program

       static void Main(string[ ] args)

       {

           int numberOfDrawers = 0;

           string deskWoodType = "o";

           double cost = 0;

           drawersMeth(numberOfDrawers);

           woodTypeMeth(deskWoodType);

           CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

           OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

       }//end main

       private static void drawersMeth(int numberOfDrawers)

       {

           int numOfDrawers;

           Console.WriteLine("Enter the number of desk drawers");

           numOfDrawers = Convert.ToInt16(Console.ReadLine());

           numberOfDrawers = numOfDrawers;

       }//end drawersMeth

       private static string woodTypeMeth(string deskWoodType)

       {

           Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

           deskWoodType = Convert.ToString(Console.ReadLine());

           switch (deskWoodType)

           {

               case "mahogany":

                   {

                       deskWoodType = "m";

                       break;

                   }

               case "oak":

                   {

                       deskWoodType = "o";

                       break;

                   }

               case "pine":

                   {

                       deskWoodType = "p";

                       break;

                   }

               default:

                   {

                       deskWoodType = "error";

                       break;

                   }

           }

           return deskWoodType;

       }// end woodTypeMeth

       private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

       {

           int pine = 100;

           int oak = 140;

           int other = 180;

           int surchage = 30;

           if (deskWoodType == "p")

               cost = surchage + (numberOfDrawers *pine );

           else if (deskWoodType == "o")

               cost = surchage + (numberOfDrawers *oak );

           else

               cost = surchage + (numberOfDrawers *other );

           return cost;

       }// end CalculateCostMeth

       private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

       {

           double totalCost = cost;

           Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

           Console.WriteLine("The wood finish you have selected is ", deskWoodType);

           Console.WriteLine("The total cost is {0}", totalCost);

       }//end outputCost

   }//end class

}//end nameSpace

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mezya [45]

Answer:

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Explanation:

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People tend to photograph these slides so make sure the information is error free and that you add you own marketing info to the slide as well.

5 0
2 years ago
What is a user data?
Rom4ik [11]

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Explanation:

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but examples of user data are intalled programs, uploads, word documents created by user (computer user)

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