When a machine says function suppressed after scanning a ticket, it implies that you have won some certain amount.
<h3>What is lottery wins?</h3>
This term connote that a person has a winning ticket in a lottery that is often owned by a government.
Note that if a winning ticket is scanned, the terminal often shows a message just for you and that suppress function implies that your the ticket has won something.
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Answer:
What does your digital footprint say about you?
Explanation:
Just follow the path from the end to the start, that's how I always get mazes.
Answer: The Progressive Era was a period of widespread social activism and political reform across the United States that spanned the 1890s to the 1920s.
Explanation:
Answer:
While loops are typically used when you don’t know how many times the loop needs to repeat. The body of the loop will repeat while the condition is true. The logical expression will be evaluated just before the body of the loop is repeated.
Let’s say that we want to find the square root of a number. For some square roots, you’re never going to be exact. Let’s say that we want to find a square root that, when multiplied by itself, is within 0.01 of the square we want. How do we do it? There’s a really old process that we can apply here.
Start by guessing 2.
Compute the guess squared.
Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)
If it’s not close enough, we divide the target number by our guess, then average that value with our guess.
That’s our new guess. Square it, and go back to Step #3.
Explanation:
Answer:
See explaination
Explanation:
#include <iostream>
using namespace std;
int main()
{
double h, w;
int s, a, b;
cout<<"height in feet: ";
cin>>h;
cout<<"width in feet: " ;
cin>>w;
cout<<"tile size in inches:";
cin>>s;
int height = h*12;
if(height%s==0)
a = height/s;
else
a = height/s + 1;
int width = w*12;
if(width%s==0)
b = width/s;
else
b = width/s + 1;
cout<<"Number of tiles: "<<a*b;
}