If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
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f (1+1)= f (1)+8
f (2)= 27+8
f (2)=35
f (2+1)= f (2)+8
f (3)= 35+8
f (3)=43
9x^3-39x^2-38x+40=(3x-2)(3x+4)(x-5) by synthetic division
Thus roots are -4/3, 2/3, 5
13/25
first off, to turn a fraction into a decimal, you divide numerator by denominator
in this case, 13/25=.52
answer is .52